Calculate voltage drop across conductors using standard formulas and compare the result to common 3% branch-circuit and 5% total guidance values.
Single-phase and three-phase voltage drop formula. K = conductor constant (Cu: 12.9, Al: 21.2), I = current (A), D = distance (ft), CM = conductor area (circular mils).
You've run 12-gauge wire 150 feet from the panel to a detached garage. A 20-amp circuit. Seems reasonable. But when the customer flips the breaker, the lights dim the second the heater kicks on. Classic voltage drop problem.
Voltage drop is the voltage loss that happens as current travels through a wire. The longer the run, the smaller the wire, the higher the current—the worse it gets. A 120V circuit that drops 5% is delivering only 114V to the load. Motors start struggling. Lights get dim. Equipment runs hot. And your callback list grows.
The NEC gives us limits: 3% for branch circuits, 5% combined. Don't ignore them. Inspectors sure won't.
The National Electrical Code doesn't call it a requirement (Article 210.19(A) is technically a recommendation), but every inspector and engineer treats it like one. Here's what you need:
At 480V, 3% = 14.4 volts. Bigger number, but same rules apply. Stay under the limits and your equipment operates at rated performance. Blow past them and you're heading for a callback—or worse, a liability issue.
Stay with us—this formula looks worse than it is:
That's it. K is the conductor constant (12.9 for copper, 21.2 for aluminum—memorize these). I is your load current in amps. D is the one-way distance in feet. CM is the wire's circular mil area (use any reference table). The 2 in single-phase? Current flows out and back, so you count the distance twice. The 1.732 in three-phase? That's just √3, accounting for the phase angle. Plug the numbers in and you've got voltage drop in volts.
So you've done the math and your circuit's pushing limits. What's the fix?
Running a 20A kitchen circuit 150 feet in 12 AWG copper? At full load you're dropping about 11.8 volts (nearly 10%). That's hosed. You need 10 AWG minimum, and honestly, 8 AWG is better. Do the math before you pull the wire, not after.
Running a 100A feeder 500 feet to a motor on 480V three-phase using 1/0 copper? You're only dropping about 8.2V (1.7%). Compliant. Three-phase saves you from needing massive wire.
Doing a solar installation? DC systems don't follow NEC voltage drop percentages, but the physics is the same. A 2 AWG aluminum run carrying 80A for 150 feet drops 19.3V. At 400V input, that's 4.8%. Acceptable for solar, but you feel the efficiency loss. Step up to 1/0 and you're golden.
Pick your voltage and phase type. Select copper or aluminum (copper every time if budget allows). Choose your wire size. Enter the one-way distance and load current. The calculator spits out your voltage drop in volts and percentage, plus NEC compliance status. Green = good. Red = you need thicker wire or a shorter run. Do yourself a favor and get it right on paper before you cut into the wall.
| AWG/kcmil | Circular Mils | Copper Resistance Ω/1000ft | Aluminum Resistance Ω/1000ft | Max Amps (Cu, 75°C) |
|---|---|---|---|---|
| 14 | 4,110 | 3.14 | 5.17 | 20 |
| 12 | 6,530 | 1.98 | 3.25 | 25 |
| 10 | 10,380 | 1.24 | 2.04 | 40 |
| 8 | 16,510 | 0.778 | 1.28 | 55 |
| 6 | 26,240 | 0.491 | 0.808 | 75 |
| 4 | 41,740 | 0.308 | 0.508 | 100 |
| 2 | 66,360 | 0.194 | 0.319 | 130 |
| 1 | 83,690 | 0.154 | 0.253 | 150 |
| 1/0 | 105,600 | 0.122 | 0.201 | 170 |
| 2/0 | 133,100 | 0.0967 | 0.159 | 195 |
| 3/0 | 167,800 | 0.0766 | 0.126 | 225 |
| 4/0 | 211,600 | 0.0608 | 0.100 | 260 |
| 250 kcmil | 250,000 | 0.0515 | 0.0847 | 290 |
| 300 kcmil | 300,000 | 0.0429 | 0.0706 | 320 |
| 350 kcmil | 350,000 | 0.0367 | 0.0605 | 350 |
| 400 kcmil | 400,000 | 0.0322 | 0.0529 | 380 |
| 500 kcmil | 500,000 | 0.0257 | 0.0424 | 430 |